Theories of failure
A simple tension test tells us when steel yields under one stress acting alone. In a real structure, a point may carry tension, compression and shear together. Theories of failure answer the question: what combination of stresses is as dangerous as the yield or fracture point found in the simple test? Each theory picks one quantity, such as maximum stress, strain, shear or distortion energy, and assumes failure when it reaches its value at uniaxial failure.
The maximum principal stress theory (Rankine) suits brittle materials like cast iron and, roughly, concrete in tension. The maximum shear stress theory (Tresca) says yield occurs when (σ₁ − σ₃)/2 reaches fy/2; it is conservative and simple. The distortion energy theory (von Mises) says yield occurs when the energy of shape change reaches its uniaxial value, giving the familiar equivalent stress formula. Tests on ductile steel agree best with von Mises, which is why steel codes use it for combined bending and shear in welds and plates. Maximum strain (St Venant) and total strain energy (Haigh) theories are of mainly historical interest.
For pure shear, Tresca predicts yield at τ = 0.5 fy and von Mises at τ = fy/√3 ≈ 0.577 fy. That second figure is the basis of shear yield strength used in steel design. Soils and rock use the Mohr–Coulomb criterion instead, because their strength grows with confining pressure.
For a quick hand check of steel under combined bending and shear, use the equivalent stress √(σ² + 3τ²) and compare it with the design strength.
Rankine: σ₁ = f_t (brittle)Tresca: σ₁ − σ₃ = fyvon Mises (plane): σe = √(σ₁² − σ₁σ₂ + σ₂²) = fyWith σ and τ: σe = √(σ² + 3τ²); pure shear yield τ_y = fy / √3
Applying a ductile-material theory such as von Mises to a brittle material like cast iron or plain concrete.
Problem. A steel plate (fy = 250 MPa) carries σ = 150 MPa and τ = 80 MPa at a point. Check yield by von Mises and Tresca.
- von Mises: σe = √(150² + 3 × 80²) = √(22 500 + 19 200) = 204 MPa < 250 MPa, safe; factor 1.22.
- Tresca: principal stresses = 75 ± √(75² + 80²) = 75 ± 109.7, so 184.7 and −34.7 MPa.
- σ₁ − σ₃ = 219.4 MPa < 250 MPa, safe; factor 1.14.
Answer. Safe by both; Tresca is the more conservative here
Quick quiz
1Which theory suits ductile steel best?
von Mises (distortion energy).
2Shear yield strength by von Mises?
fy / √3, about 0.577 fy.
3Which theory suits brittle materials?
Maximum principal stress (Rankine).
- IS 800 (India): General construction in steel: limit state design of steel members and connections.
Clauses and documents to read
- IS 800:2007 cl. 10.5.10.1 (combined stresses in fillet welds)
Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.
References and further reading
Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.
- J. M. Gere, B. J. Goodno, Mechanics of Materials, Cengage, latest edition.
- F. P. Beer, E. R. Johnston, J. T. DeWolf, Mechanics of Materials, McGraw Hill, latest edition.
- E. P. Popov, Engineering Mechanics of Solids, Prentice Hall, 2nd edition.
Free and official sources
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