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Horizontal curves and superelevation

Intermediate Highway Engineering Reviewed 24 Oct 2026 2 min read

When a vehicle travels round a horizontal curve, it needs a force towards the centre of the curve to keep turning. That force comes from side friction between tyres and road, helped by tilting the road inward. The tilt is superelevation, e. Without enough of it, a fast vehicle tends to skid outward or, if it has a high centre of gravity, overturn.

Balancing forces gives e + f = V² / (127 R), with V in km/h, R in metres and f the design lateral friction coefficient. Indian practice limits f to about 0.15 and caps superelevation at 7 percent on plain and rolling terrain and in snow-bound areas, 10 percent on hill roads not bound by snow, and about 4 percent on urban stretches with frequent intersections, so a minimum radius follows for each design speed. Designers first check the superelevation that would counteract 75 percent of design speed without friction; if that exceeds the limit, they cap e and check that friction stays within limits at full design speed. If not, speed must be restricted or a flatter curve used.

Diagram: Indiacon original, not to scale.

Superelevation is introduced gradually over the transition length, rotating the pavement about the centre line or an edge. Extra widening is added on sharp curves because rear wheels track inside front wheels and drivers keep away from the edge. Sight distance on the inside of the curve must be kept clear by setting back buildings and cutting slopes, the set-back distance. Consistency matters: a sharp curve after a long straight is a classic crash site.

Key formulas
  • e + f = V² / (127 R)
  • Design check: e = (0.75 V)² / (127 R), capped at e_max
  • Minimum radius: R_min = V² / [127 (e_max + f)]
  • Mechanical widening: W_m = n l² / (2R); psychological: V / (9.5 √R)
Solved example

Problem. Design superelevation for a curve of R = 300 m at a design speed of 80 km/h, with e_max = 0.07 and f = 0.15.

  1. e for 75 percent speed: (0.75 × 80)² / (127 × 300) = 3 600 / 38 100 = 0.094 > 0.07, so adopt e = 0.07.
  2. Check friction at full speed: f = 80² / (127 × 300) − 0.07 = 0.168 − 0.07 = 0.098 < 0.15. Safe.
  3. Minimum radius check: 80² / (127 × 0.22) = 229 m < 300 m, so the curve is acceptable.

Answer. Use e = 7 percent; friction needed 0.098, within 0.15

Quick quiz

1What provides centripetal force on a curve?

Side friction plus superelevation.

2Why add extra widening on sharp curves?

Rear wheels track inside front wheels, and drivers keep away from the edge.

3What is set-back distance?

The clearance needed inside a curve to preserve sight distance.

Code note
  • IRC:73 (India): Geometric design standards for rural (non-urban) highways.
  • IRC:86 (India): Geometric design standards for urban roads.

Clauses and documents to read

  • IRC:73-2023 (geometric design standards for non-urban roads: superelevation and radius)
  • IRC:38-1988 (horizontal curves and design tables)
  • IRC:SP:23-1993 (vertical curves, related)

Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • S. K. Khanna, C. E. G. Justo, A. Veeraragavan, Highway Engineering, Nem Chand and Bros, latest edition.
  • F. L. Mannering, S. S. Washburn, Principles of Highway Engineering and Traffic Analysis, Wiley, latest edition.

Free and official sources

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