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Pile capacity

Intermediate Geotechnical and Foundation Engineering Reviewed 24 Oct 2026 2 min read

A pile carries load in two ways: through its base, by end bearing on a firm stratum, and along its shaft, by friction or adhesion with the surrounding soil. Long piles in clay are mostly friction piles; short piles to rock are mostly end-bearing. The ultimate capacity is the sum of both, and a factor of safety (commonly 2.5 on static formulas) gives the safe working load.

In clay, shaft resistance is the adhesion factor α times undrained strength times shaft area, with α falling as clay gets stiffer. Base resistance is about nine times cu times the base area. In sand, shaft friction depends on effective overburden, an earth pressure coefficient and the interface friction angle; base resistance uses a bearing capacity factor Nq times the effective overburden at the toe. Beyond a critical depth these values level off. Driven piles densify sand and gain capacity; bored piles may loosen it.

Diagram: Indiacon original, not to scale.

Because formulas carry uncertainty, codes require load tests. Initial tests on trial piles confirm design; routine tests on working piles check construction. Static vertical load tests measure settlement under increments; dynamic tests with strain gauges and accelerometers, and integrity tests by low-strain sonic methods, are faster. Negative skin friction, where consolidating fill drags the pile down, can cut capacity sharply and must be allowed for.

Tip

Plan the initial load test early, before working piles are ordered, so the design can be adjusted.

Key formulas
  • Q_u = Q_b + Q_s
  • Clay: Q_s = α cu As; Q_b = 9 cu Ab
  • Sand: Q_s = K σ′v tan δ As; Q_b = σ′v Nq Ab
  • Safe load: Q_safe = Q_u / FS (typically 2.5)
Common mistake

Counting shaft friction through soft fill that is still settling, where the fill actually drags the pile down.

Solved example

Problem. A 600 mm bored pile 15 m long in uniform clay with cu = 60 kPa. Take α = 0.5. Find ultimate and safe capacity (FS 2.5).

  1. Shaft area = π × 0.6 × 15 = 28.27 m²; Qs = 0.5 × 60 × 28.27 = 848 kN.
  2. Base area = π × 0.6² / 4 = 0.283 m²; Qb = 9 × 60 × 0.283 = 153 kN.
  3. Qu = 1 001 kN.
  4. Safe load = 1 001 / 2.5 ≈ 400 kN.

Answer. Ultimate ≈ 1 000 kN; safe ≈ 400 kN

Quick quiz

1Name the two components of pile capacity.

End bearing and shaft friction.

2What base factor is used for clay?

About 9 (Nc).

3What is negative skin friction?

Downward drag on a pile from consolidating soil around it.

Code note
  • IS 2911 (series) (India): Design and construction of pile foundations.

Clauses and documents to read

  • IS 2911 (Part 1/Sec 2):2010 Annex B (static formulas)
  • IS 2911 (Part 4):2013 (load test on piles)
  • IS 14893:2001 (pile integrity testing)

Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • B. M. Das, Principles of Foundation Engineering, Cengage, latest edition.
  • J. E. Bowles, Foundation Analysis and Design, McGraw Hill, 5th edition.
  • M. J. Tomlinson, Pile Design and Construction Practice, CRC Press, latest edition.

Free and official sources

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