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Dimensional analysis

Intermediate Fluid Mechanics and Hydraulics Reviewed 24 Oct 2026 2 min read

Dimensional analysis uses the fact that every valid physical equation must be dimensionally consistent to reduce the number of variables in a problem. Instead of studying how pipe friction depends separately on velocity, diameter, roughness, density and viscosity, we find a few dimensionless groups, such as Reynolds number and relative roughness, and study how the dimensionless head loss depends on those. Fewer variables mean fewer experiments and results that apply at any scale.

Buckingham's Pi theorem states that a problem with n variables and m fundamental dimensions (mass, length, time) can be described by n − m independent dimensionless groups. Rayleigh's method is a simpler approach for problems with few variables. The common groups in hydraulics are the Reynolds number (inertia to viscous forces), the Froude number (inertia to gravity), the Weber number (inertia to surface tension), the Euler number (pressure to inertia) and the Mach number (inertia to elasticity).

v = k i
Diagram: Indiacon original, not to scale.

This underpins hydraulic model studies. A scale model of a spillway, harbour or river reach behaves like the prototype if the governing dimensionless number is the same in both. Open channel and free-surface flows are dominated by gravity, so Froude similarity is used: velocities scale with the square root of the length scale and discharges with the length scale to the power 2.5. Exact similarity of all numbers at once is rarely possible, so scale effects are judged and models are kept large enough that viscous and surface tension effects are small.

Key formulas
  • Pi theorem: number of groups = n − m
  • Re = ρ V L / μ; Fr = V / √(g L); We = ρ V² L / σ
  • Froude model scaling: V_r = L_r^0.5; Q_r = L_r^2.5; T_r = L_r^0.5
  • Force ratio: F_r = L_r³ (Froude, same fluid)
Solved example

Problem. A 1:40 spillway model is run with Froude similarity. The prototype design flood is 3 200 m³/s. What model discharge is needed, and what prototype velocity corresponds to 1.5 m/s in the model?

  1. Q_r = 40^2.5 = 10 119.
  2. Model Q = 3 200 / 10 119 = 0.316 m³/s = 316 L/s.
  3. V_r = 40^0.5 = 6.32; prototype velocity = 1.5 × 6.32 = 9.5 m/s.

Answer. About 316 L/s in the model; about 9.5 m/s in the prototype

Quick quiz

1How many dimensionless groups for 6 variables in M, L, T?

Three.

2Which similarity law is used for spillway models?

Froude similarity.

3Why can't all dimensionless numbers be matched at once?

Using the same fluid at a smaller scale makes it impossible; scale effects must be judged.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • P. N. Modi, S. M. Seth, Hydraulics and Fluid Mechanics including Hydraulic Machines, Standard Book House, latest edition.
  • V. T. Chow, Open-Channel Hydraulics, McGraw Hill, 1959.
  • K. Subramanya, Flow in Open Channels, McGraw Hill Education (India), latest edition.

Free and official sources

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