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Areas and volumes

Intermediate Surveying Reviewed 24 Oct 2026 2 min read

Quantities of land and earthwork are among the most frequent survey outputs, used for land acquisition, payment, planning of haul and checking of reservoirs. Areas come from coordinates, from offsets to irregular boundaries, or by planimeter or software on a map. Volumes come from cross-sections, spot heights or surface models.

For a polygon defined by coordinates, the coordinate (shoelace) method gives the area exactly. For an irregular boundary measured by offsets at regular intervals from a baseline, the trapezoidal rule treats each strip as a trapezium, while Simpson's one-third rule fits parabolas through sets of three offsets and is more accurate for curved boundaries, but needs an odd number of offsets.

Diagram: Indiacon original, not to scale.

Earthwork volumes for roads, canals and embankments are computed from cross-sectional areas taken at regular stations. The average end area method multiplies the mean of two end areas by the distance between them; it overestimates for shapes that taper. The prismoidal formula, which uses a middle section too, is exact for prismoids and is used for payment where specified. Spot heights on a grid give volumes for site levelling and borrow pits. Software compares two digital terrain models directly. A mass-haul diagram, built from cumulative cut and fill corrected for bulking or shrinkage, shows how far material must travel and where to balance cut against fill.

Tip

Take cross-sections at every change of ground slope as well as at regular stations.

Key formulas
  • Coordinates: A = ½ |Σ (xᵢ yᵢ₊₁ − xᵢ₊₁ yᵢ)|
  • Trapezoidal: A = d [(o₁ + oₙ)/2 + o₂ + … + oₙ₋₁]
  • Simpson: A = (d/3)[o₁ + oₙ + 4 Σ even + 2 Σ odd interior]
  • Prismoidal: V = (L/6)(A₁ + 4Am + A₂); end area: V = L (A₁ + A₂)/2
Common mistake

Using the end area method between a cut section and a fill section; split at the zero line first.

Solved example

Problem. Offsets at 10 m spacing are 3.2, 5.1, 6.4, 5.8 and 4.0 m. Find the area by trapezoidal and Simpson rules.

  1. Trapezoidal: 10 × [(3.2 + 4.0)/2 + 5.1 + 6.4 + 5.8] = 10 × [3.6 + 17.3] = 209.0 m².
  2. Simpson (5 offsets): (10/3) × [3.2 + 4.0 + 4 × (5.1 + 5.8) + 2 × 6.4].
  3. = 3.333 × [7.2 + 43.6 + 12.8] = 3.333 × 63.6 = 212.0 m².

Answer. 209 m² (trapezoidal), 212 m² (Simpson)

Quick quiz

1What does Simpson's rule require?

An odd number of offsets (even number of strips).

2Does the end area method over- or under-estimate for tapering shapes?

It overestimates.

3What does a mass-haul diagram show?

Cumulative cut and fill, and hence haul distances and balance points.

Code note
  • IS 1200 (series) (India): Method of measurement of building and civil engineering works, one part per trade.

Clauses and documents to read

  • IS 1200 (Part 1):1992 (earthwork measurement)

Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • S. K. Duggal, Surveying (Vols 1 and 2), McGraw Hill Education (India), latest edition.
  • B. C. Punmia, A. K. Jain, A. K. Jain, Surveying (Vols 1 to 3), Laxmi Publications, latest edition.
  • C. D. Ghilani, P. R. Wolf, Elementary Surveying: An Introduction to Geomatics, Pearson, latest edition.

Free and official sources

All references for this subject →

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