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Critical state concepts

Advanced and Design Soil Mechanics Reviewed 24 Oct 2026 2 min read

Critical state soil mechanics ties together strength and volume change. When a soil is sheared far enough, it reaches a critical state in which it keeps deforming at constant shear stress, constant effective stress and constant volume. All samples of the same soil, whatever their starting density, end on one line in stress space, the critical state line, where the ratio of deviator stress to mean effective stress is a constant, M.

Where a sample starts relative to that line decides how it gets there. Loose sands and normally consolidated clays are on the wet side: they contract as they are sheared, and in undrained tests positive pore pressures build up and reduce effective stress. Dense sands and heavily overconsolidated clays are on the dry side: they dilate, show a peak strength above the critical value, and soften towards it; undrained, they develop negative pore pressures.

density k
Diagram: Indiacon original, not to scale.

The parameter M is linked to the critical-state friction angle. In triaxial compression, M equals 6 sin φ over 3 minus sin φ. This angle is a property of the soil grains and their arrangement and does not depend on density, which makes it a reliable design parameter for large strains, for example in slopes that have already slipped.

The Cam clay and modified Cam clay models build on these ideas, adding a yield surface that grows with consolidation, and are widely used in numerical analysis of embankments on soft clay, excavations and foundations. They explain why the undrained strength of a normally consolidated clay is roughly proportional to its consolidation stress.

Tip

Use the critical-state angle for large-strain problems such as reactivated slips.

Key formulas
  • Critical state line: q = M p′
  • Triaxial compression: M = 6 sin φ_cs / (3 − sin φ_cs)
  • Undrained strength at critical state: c_u = q / 2
Common mistake

Using a dense sand's peak angle in a problem where large strains will occur.

Solved example

Problem. A clay has φ_cs = 30°. In an undrained triaxial compression test it reaches critical state at p′ = 200 kPa. Find M, the deviator stress and the undrained shear strength.

  1. sin 30° = 0.5, so M = 6 × 0.5 / (3 − 0.5) = 3 / 2.5 = 1.2.
  2. q = M p′ = 1.2 × 200 = 240 kPa.
  3. c_u = q / 2 = 120 kPa.

Answer. M = 1.2, q = 240 kPa, c_u = 120 kPa

Quick quiz

1What stays constant at the critical state?

Shear stress, effective stress and volume.

2How does a dense sand behave on shearing?

It dilates, shows a peak and softens towards the critical state.

3Does φ_cs depend on initial density?

No.

Code note
  • IS 2720 (series) (India): Methods of test for soils: water content, limits, compaction, shear and others, each in its own part.
  • EN 1997 (Eurocode 7) (Europe): Geotechnical design.

Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • Gopal Ranjan, A. S. R. Rao, Basic and Applied Soil Mechanics, New Age International, latest edition.
  • B. M. Das, Principles of Geotechnical Engineering, Cengage, latest edition.
  • K. Terzaghi, R. B. Peck, G. Mesri, Soil Mechanics in Engineering Practice, Wiley, 3rd edition.
  • J. A. Knappett, R. F. Craig, Craig's Soil Mechanics, CRC Press, latest edition.

Free and official sources

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