Loads and load paths in a building
Every load in a building must travel, member by member, down to the soil. This route is the load path. A floor tile's weight goes into the slab, the slab bends and passes it to beams, beams carry it to columns, columns to footings, and footings spread it into the ground. A designer who can trace that path for every type of load rarely makes a fundamental error.
Loads are grouped by nature. Dead loads are the self-weight of the structure and permanent finishes, partitions and services; they are calculated from dimensions and unit weights. Imposed (live) loads depend on use: a residential floor, an office, a library store or an assembly hall each has a code value per square metre. Wind pressure depends on location, height, terrain and building shape. Earthquake forces come from the building's mass and stiffness and the seismic zone. Snow, temperature, soil and water pressure, and construction loads complete the list.
Because these loads do not all peak at the same time, codes specify combinations with partial safety factors, larger for less certain loads. Lateral loads need their own path: diaphragm action of slabs carries wind or seismic force to frames, shear walls or braced bays and then to the foundations. Weak links in the lateral path, such as a soft storey with open parking, floating columns or missing ties, are among the main causes of collapse in earthquakes.
Dead load of slab: g = thickness × unit weight (RC ≈ 25 kN/m³)Load on beam from one-way slab: w = (g + q) × tributary widthTypical limit state combination: 1.5 (DL + LL)With wind or earthquake: 1.2 (DL + LL + WL/EL) or 1.5 (DL + WL/EL), or 0.9 DL + 1.5 WL/EL
Problem. A 150 mm RC slab with 1.0 kN/m² finishes and 2.0 kN/m² imposed load spans one way onto beams at 4 m centres. Find the factored load per metre on an interior beam, excluding its own weight.
- Slab self-weight = 0.15 × 25 = 3.75 kN/m². Total dead = 4.75 kN/m².
- Service load = 4.75 + 2.0 = 6.75 kN/m².
- Tributary width = 4 m, so service load on the beam = 27 kN/m.
- Factored = 1.5 × 27 = 40.5 kN/m.
Answer. 40.5 kN/m factored (plus the beam's own weight)
Quick quiz
1What is a load path?
The route by which load passes from member to member down to the soil.
2Name two lateral load-resisting systems.
Moment frames, shear walls or braced frames.
3Why are partial safety factors different for different loads?
Some loads are less certain than others.
- IS 456 (India): Plain and reinforced concrete: general rules for materials, durability, design and construction.
- IS 875 (Parts 1 to 5) (India): Design loads other than earthquake: dead, imposed, wind, snow and load combinations.
- IS 1893 (Part 1) (India): Criteria for earthquake-resistant design: seismic zones and how to work out earthquake forces.
Clauses and documents to read
- IS 875 (Part 1):1987 (dead loads, unit weights)
- IS 875 (Part 2):1987 (imposed loads)
- IS 875 (Part 3):2015 (wind loads)
- IS 1893 (Part 1):2016 (earthquake loads)
- IS 456:2000 cl. 36.4 (load combinations)
Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.
References and further reading
Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.
- S. Unnikrishna Pillai, Devdas Menon, Reinforced Concrete Design, McGraw Hill Education (India), latest edition.
- J. K. Wight, J. G. MacGregor, Reinforced Concrete: Mechanics and Design, Pearson, latest edition.
- A. H. Nilson, D. Darwin, C. W. Dolan, Design of Concrete Structures, McGraw Hill, latest edition.
- R. Park, T. Paulay, Reinforced Concrete Structures, Wiley, 1975.
Free and official sources
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